Struct template as_expr

| Home | Libraries | People | FAQ | More

## Struct template as_expr

boost::proto::result_of::as_expr — A metafunction that computes the return type of the `proto::as_expr()` function.

## Synopsis

    // In header: <boost/proto/traits.hpp>

    template<typename T, typename Domain = proto::default_domain>
    struct as_expr {
      // types
      typedef see-below type;
    };

## Description

The `proto::result_of::as_expr<>` metafunction turns types into Proto types if they are not already, by making them Proto terminals held by value if possible. Types which are already Proto types are left alone.

If `T` is not yet a Proto type, the resulting terminal type is calculated as follows:

If `T` is a function type, let `A` be `T &`. Otherwise, let `A` be the type `T` stripped of cv-qualifiers. Then, the result type `proto::result_of::as_expr<T, Domain>::type` is `boost::result_of<Domain(proto::expr< proto::tag::terminal, proto::term<A> >)>::type`.